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JEE MAIN - Physics (2024 - 30th January Morning Shift - No. 25)

The distance between object and its two times magnified real image as produced by a convex lens is $$45 \mathrm{~cm}$$. The focal length of the lens used is _______ cm.
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$$\begin{aligned} & \frac{v}{u}=-2 \\ & v=-2 u \quad\text{... (i)} \\ & v-u=45 \quad\text{... (ii)}\\ & \Rightarrow u=-15 \mathrm{~cm} \\ & v=30 \mathrm{~cm} \\ & \frac{1}{f}=\frac{1}{v}-\frac{1}{u} \\ & f=+10 \mathrm{~cm} \end{aligned}$$

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